It would appear to any observer as though light from the object were diverging from this location. The point of their intersection is the virtual image location. Light rays diverge upon refraction for this reason, the image location can only be found by extending the refracted rays backwards on the object's side the lens. A six-foot tall person would have an image that is larger than six feet tall. In this case, the image is enlarged in other words, the image dimensions are greater than the object dimensions. That is to say, if the object is right side up, then the image will also be right side up. In this case, the image will be an upright image. Regardless of exactly where in front of F the object is located, the image will always be located on the object's side of the lens and somewhere further from the lens. When the object is located at a location in front of the focal point, the image will always be located somewhere on the same side of the lens as the object. After refracting, the light rays are traveling parallel to each other and cannot produce an image.Ĭase 5: The object is located in front of F As discussed earlier in Lesson 5, the refracted rays neither converge nor diverge. When the object is located at the focal point, no image is formed. As such, the image of the object could be projected upon a sheet of paper. Light rays actually converge at the image location. The absolute value of the magnification is greater than 1. The image dimensions are larger than the object dimensions. In this case, the image will be inverted (i.e., a right side up object results in an upside-down image). Regardless of exactly where the object is located between 2F and F, the image will be located in the specified region. When the object is located in front of the 2F point, the image will be located beyond the 2F point on the other side of the lens. As such, the image of the object could be projected upon a sheet of paper.Ĭase 3: The object is located between 2F and F A six-foot tall person would have an image that is six feet tall the absolute value of the magnification is exactly 1. The image dimensions are equal to the object dimensions. When the object is located at the 2F point, the image will also be located at the 2F point on the other side of the lens. If a sheet of paper were placed at the image location, the actual replica or likeness of the object would appear projected upon the sheet of paper. In this case, the magnification is a number with an absolute value less than 1. Earlier in Unit 13, the term magnification was introduced the magnification is the ratio of the height of the object to the height of the image. If the object is a six-foot tall person, then the image is less than six feet tall. In this case, the image is reduced in size in other words, the image dimensions are smaller than the object dimensions. That is to say, if the object is right side up, then the image is upside down. In this case, the image will be an inverted image. Regardless of exactly where the object is located, the image will be located in this specified region. When the object is located at a location beyond the 2F point, the image will always be located somewhere in between the 2F point and the focal point (F) on the other side of the lens. Case 5: the object is located in front of the focal point (F).Case 4: the object is located at the focal point (F).Case 3: the object is located between the 2F point and the focal point (F).Case 2: the object is located at the 2F point.Case 1: the object is located beyond the 2F point.The best means of summarizing this relationship is to divide the possible object locations into five general areas or points: The purpose of this portion of the lesson is to summarize these object-image relationships. Perhaps you noticed that there is a definite relationship between the image characteristics and the location where an object placed in front of a double convex lens. Previously in Lesson 5, ray diagrams were constructed in order to determine the general location, size, orientation, and type of image formed by double convex lenses.
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